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| Quadrilateral IV http://mathhelpplanet.com/viewtopic.php?f=28&t=39715 |
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| Автор: | L-Br [ 21 мар 2015, 02:32 ] |
| Заголовок сообщения: | Quadrilateral IV |
Let ABCD and GFED square where AG=10 where P,Q are midpoint of AE and GC. Determine PQ. ![]() answer: 5sqrt(2) Guys, it doenst even say a ratio between side of squares. Is it possible to solve without this ratio? |
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| Автор: | Anatole [ 21 мар 2015, 03:04 ] |
| Заголовок сообщения: | Re: Quadrilateral IV |
L-Br [math]O[/math] - center [math]\frac{ \boldsymbol{O} \boldsymbol{P} }{ \boldsymbol{C} \boldsymbol{E} }=\frac{ AO }{AC } =\frac{ 1 }{ 2 }[/math] [math]OP=5[/math] [math]POQ[/math] - [math]\triangle , \measuredangle POQ=90^{\circ}, OP=OQ[/math] [math]PQ[/math]-gipotenuza |
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| Автор: | Dotsent [ 21 мар 2015, 06:48 ] |
| Заголовок сообщения: | Re: Quadrilateral IV |
L-Br Try to prove a useful property of a trapezoid: The length of the segment joining the midpoints of the diagonals is equal to half the difference between the length of the bases |
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| Автор: | L-Br [ 21 мар 2015, 14:57 ] |
| Заголовок сообщения: | Re: Quadrilateral IV |
Thanks guys! By the way, I totally forgot this property
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