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| Polygon http://mathhelpplanet.com/viewtopic.php?f=28&t=39488 |
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| Автор: | L-Br [ 10 мар 2015, 02:54 ] |
| Заголовок сообщения: | Polygon |
Let ABCDE an regular pentagon where AB=BT , BD=BK and TK=2sqrt(5) . Determine CH ![]() Answer: sqrt(5) |
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| Автор: | Dotsent [ 10 мар 2015, 20:03 ] |
| Заголовок сообщения: | Re: Polygon |
Calculate angles and prove that х=СН |
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| Автор: | L-Br [ 11 мар 2015, 00:59 ] |
| Заголовок сообщения: | Re: Polygon |
Dotsentet, You did like this ↓ , am i right? ( I omit the new regular pentagon that you had drawn) ![]() But i dont know how to prove it :/ By the way, How do we know that BQ (diagonal) and TK intercept forming exactly PK equal CH?
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| Автор: | Dotsent [ 11 мар 2015, 06:00 ] |
| Заголовок сообщения: | Re: Polygon |
Calculate angles and prove that BTQK - parallelogram, so G is the midpoint of BQ and TK... |
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